Standard Knowledge¶

Logarithm¶

$Log_{10}(200)=2.3$ because $200=10^{2.3}$

$Log_{10}(10^x)=x$

i-th Logarithm:

What to raise i in to get the result.

$log_i(x)$ : solve equation:

find y: $x=i^y$

$\frac{a}{c}\cdot\frac{b}{d}=\frac{ab}{cd}$

$\frac{a}{b}:\frac{c}{d}=\frac{a}{b}\cdot\frac{d}{c}$

Last update: February 20, 2019